15 public questions tagged with this topic.
β-Keto acids undergo decarboxylation more easily due to the stability of the enolate intermediate. This follows from NCERT principle where relation explains outcome clearly for students.
Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Some Basic Concepts, Structure of Atom, Periodicity and relevant Chemistry topic, Topic: Mole concept and periodic trends.
β-Keto acids undergo decarboxylation easily due to the stability of the enolate intermediate. This follows from NCERT principle where the relation explains the outcome clearly for students in simple steps.
Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Some Basic Concepts, Structure of Atom and Periodicity, Topic: Mole concept, atomic models and periodic trends.
Benzyl halides hydrolyze easily due to resonance stabilization of the carbocation formed. This follows from NCERT principle where the relation explains the outcome clearly for students in simple steps.
Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Some Basic Concepts, Structure of Atom and Periodicity, Topic: Mole concept, atomic models and periodic trends.
Phenol reacts with bromine water to form 2, 4, 6-tribromophenol, which precipitates as a white solid. This follows from latest NCERT 2026-27 principle explaining the concept clearly for NEET students in simple steps as per rationalized syllabus.
Ref: NCERT Chemistry Textbook - Latest Edition for Academic Session 2026-27 (Rationalized Textbook for Class XI and XII)Topic: Mole concept, atomic structure, chemical formulas like H₂O, CO₂, CH₃CH₂NH₂ and periodic trends.
Benzaldehyde reacts with a Grignard reagent followed by hydrolysis to form benzophenone. This follows from latest NCERT 2026-27 principle explaining the concept clearly for NEET students in simple steps as per rationalized syllabus.
Ref: NCERT Chemistry Textbook - Latest Edition for Academic Session 2026-27 (Rationalized Textbook for Class XI and XII)Topic: Mole concept, atomic structure, chemical formulas like H₂O, CO₂, CH₃CH₂NH₂ and periodic trends.
Dichromate (Cr 2 O 7 2− ) converts to chromate (CrO 4 2− ) in alkaline medium: Cr 2 O 7 2− + 2OH − → 2CrO 4 2− + H 2 O. The solution turns yellow due to chromate formation.
Ref: NCERT Class 12 Chemistry > Chapter 4: d and f Block Elements > Topic: Preparation and Properties of Potassium Dichromate and Permanganate
Initial: [A] = 2 M , [B] = 2 M , [C] = 0 . Let 3x be moles of C formed, so A and B decrease by 2x . At equilibrium: [A] = 2 - 2x , [B] = 2 - 2x , [C] = 3x . Kc = ([C]³/[A]²[B]²) = ((3x)³/(2 - 2x)² (2 - 2x)²) = (27x³/(2 - 2x)⁴) = 64 , (27x³/(2 - 2x)⁴) = 64 , (3x/2 - 2x) = 4 , 3x = 8 - 8x , 11x = 8 , x ≈ 0.727 , [C] = 3 × 0.727 ≈ 2.18 M .
Ref: NCERT Class 11 Chemistry > Chapter 6: Equilibrium > Topic: Homogeneous and Heterogeneous Equilibria and Applications of Equilibrium Constant
Initial: [A] = (0.8/2) = 0.4 M , [B] = (0.1/2) = 0.05 M , [C] = 0 . Let x = [C] , [A] = 0.4 - 2x , [B] = 0.05 + x . Kc = ([B][C]/[A]²) = ((0.05 + x)x/(0.4 - 2x)²) = 0.0625 . Solving, (0.05 + x)x = 0.0625 (0.4 - 2x)² , test x = 0.05 : (0.05 + 0.05) × 0.05 = 0.005 , 0.0625 × (0.4 - 0.1)² = 0.005625 (close), x ≈ 0.05 M .
Ref: NCERT Class 11 Chemistry > Chapter 6: Equilibrium > Topic: Homogeneous and Heterogeneous Equilibria and Applications of Equilibrium Constant
Let [N₂] = [O₂] = x , [NO] = 0.4 - 2x . Kc = ([N₂][O₂]/[NO]²) = (x²/(0.4 - 2x)²) = 4 . Taking square root, (x/0.4 - 2x) = 2 , x = 0.8 - 4x , 5x = 0.8 , x = 0.16 M .
Ref: NCERT Class 11 Chemistry > Chapter 6: Equilibrium > Topic: Acid-Base Theories - Arrhenius Bronsted-Lowry Lewis and Salts Hydrolysis
Kc = ([Z]²/[X][Y]) = 25 . Substituting, 25 = ((0.5)²/[X](0.02)) = (0.25/0.02 [X]) , 25 × 0.02 [X] = 0.25 , 0.5 [X] = 0.25 , [X] = 0.5 M .
Ref: NCERT Class 11 Chemistry > Chapter 6: Equilibrium > Topic: Acid-Base Theories - Arrhenius Bronsted-Lowry Lewis and Salts Hydrolysis
At equilibrium, [CO] = [H₂O] = 0.2 - 0.08 = 0.12 M , [CO₂] = [H₂] = 0.08 M . Thus, Kc = ([CO₂][H₂]/[CO][H₂O]) = ((0.08)²/(0.12)²) = (0.0064/0.0144) ≈ 0.444 .
Ref: NCERT Class 11 Chemistry > Chapter 6: Equilibrium > Topic: Acid-Base Theories - Arrhenius Bronsted-Lowry Lewis and Salts Hydrolysis
Initial: [A] = 0.4 M , [B] = [C] = 0 . Let x = [B] = [C] , [A] = 0.4 - 2x . Kc = ([B][C]/[A]²) = (x²/(0.4 - 2x)²) = 0.04 , (x/0.4 - 2x) = 0.2 , x = 0.08 - 0.4x , x ≈ 0.057 M .
Ref: NCERT Class 11 Chemistry > Chapter 6: Equilibrium > Topic: Acid-Base Theories - Arrhenius Bronsted-Lowry Lewis and Salts Hydrolysis
