Practice question
Question
For the equilibrium 2NO(g) <=> N₂(g) + O₂(g) , if Kc = 4 and initial concentration of NO is 0.4 M with no products, what is [N₂] at equilibrium?
Explanation
Let [N₂] = [O₂] = x , [NO] = 0.4 - 2x . Kc = ([N₂][O₂]/[NO]²) = (x²/(0.4 - 2x)²) = 4 . Taking square root, (x/0.4 - 2x) = 2 , x = 0.8 - 4x , 5x = 0.8 , x = 0.16 M .
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