Practice question
Question
How many grams of MgCl₂ (molar mass = 95 g/mol) are needed to prepare 500 mL of a 0.3 M solution?
Explanation
Moles of MgCl₂ = 0.3 × 0.5 = 0.15 mol . Mass = 0.15 × 95 = 14.25 g .
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