Practice question
Question
Calculate the heat absorbed when 54 g of water is heated from 20°C to 80°C at constant pressure. (Cp = 75.3 J/mol·K, molar mass = 18 g/mol)
Explanation
Moles = 54 / 18 = 3 mol, Δ T = 80 - 20 = 60 K, qp = nCpΔ T = 3 × 75.3 × 60 = 13554 J = 13.55 kJ.