Practice question
Question
Calculate the heat absorbed when 50 g of copper is heated from 25°C to 125°C at constant volume. (Cv = 22.6 J/mol·K, molar mass = 63.5 g/mol)
Explanation
Moles = 50 / 63.5 = 0.7874 mol, Δ T = 125 - 25 = 100 K, qv = nCvΔ T = 0.7874 × 22.6 × 100 = 1779.5 J = 1.78 kJ.