Practice question
Question
A solution of two volatile liquids has vapor pressures of 400 mm Hg and 600 mm Hg. If the mole fraction of the first component in the liquid phase is 0.5 and the total vapor pressure is 480 mm Hg, what is the vapor pressure lowering of the first component?
Explanation
Pure P₁⁰ = 400 mm Hg . In solution: P₁ = P₁⁰ · x₁ = 400 × 0.5 = 200 mm Hg . Vapor pressure lowering = P₁⁰ - P₁ = 400 - 200 = 200 mm Hg .
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