Practice question
Question
A solution contains 10 ppm of SO₂ by mass in water. What is the molarity if the density of the solution is 1 g/mL? (Molar mass: SO₂ = 64 g/mol)
Explanation
10 ppm = 10 g SO₂ in 10⁶ g solution. Volume = 1000 L. Moles = 10/64 ≈ 0.15625 mol; molarity = 0.15625/1000 ≈ 1.5625 × 10⁻⁴ M.
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