Practice question

MCQ

Question

A solution contains 10 ppm of K₂SO₄ by mass in water. What is its molality? (Molar mass: K₂SO₄ = 174 g/mol)

Options

Choose one · Correct answer highlighted

5.0 × 10⁻⁵ m 6.0 × 10⁻⁵ m 5.75 × 10⁻⁵ m Correct 4.5 × 10⁻⁵ m

Explanation

10 ppm = 10 g K₂SO₄ in 10⁶ g water. Moles = 10/174 ≈ 0.0575 mol. Mass of solvent = 1000 kg. Molality = 0.0575/1000 ≈ 5.75 × 10⁻⁵ m.

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