A solution of two volatile liquids has vapor pressures of 300 mm Hg and 400 mm Hg for pure components. If the mole fract
Vapor phase: y₂ = (P₂⁰ · x₂/Ptotal) . 0.6 = (400 · x₂/Ptotal) . Liquid phase: Ptotal = 300 (1 - x₂) + 400 x₂ . Substitute: 0.6 Ptotal = 400 x₂ , Ptotal = 300 + 100 x₂ . 0.6 (300 + 100 x₂) = 400 x₂ , 180 + 60 x₂ = 400 x₂ , 340 x₂ = 180 , x₂ = (180/340) ≈ 0.5294 . Ptotal = 300 (1 - 0.5294) + 400 × 0.5294 ≈ 352.96 mm Hg .
Ref: NCERT Class 12 Chemistry > Chapter 1: Solutions > Topic: Types of Solutions and Expressing Concentration