A mass of \( 1.5 \, \text{kg} \) on a spring with \( k = 150 \, \text{N/m} \) has \( A = 12 \, \text{cm} \). What is the
**Energy in SHM** interconverts between kinetic K = ½ m v² = ½ m ω² (A² - x²) and potential U = ½ k x² = ½ m ω² x², total E = K + U = ½ k A² = ½ m ω² A² constant, independent of time. At mean position x=0, E = K_max = ½ m ω² A², at extremes x=±A, E = U_max = ½ k A². Total energy: E = (1/2) k A² = 0.5 × 150 × (0.12)² = 1.08 J . Potential energy: U = (1/2) k x² = 0.5 × 150 × (0.06)² = 0.27 J .
Ref: NCERT > Physics Book > Oscillations > Energy in SHM - Kinetic, Potential and Total