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Moles of solute = (6/120) = 0.05 mol . Volume = 300 mL = 0.3 L. Molarity = (0.05/0.3) ≈ 0.1667 M .
Ref: NCERT Class 12 Chemistry > Chapter 1: Solutions > Topic: Solubility - of Solids and Gases in Liquids Henry's Law
Moles of NaOH = 4/40 = 0.1 mol. Molarity = moles/volume; 0.1 = 0.1 / V; V = 1 L.
Ref: NCERT Class 11 Chemistry > Chapter 1: Some Basic Concepts of Chemistry > Topic: Importance and Nature of Chemistry and Properties of Matter
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