We use cookies to improve your experience and understand how Examtube is used. You can accept analytics cookies or continue with essential cookies only.
Privacy policy2 public questions tagged with this topic.
Δ H = [3(-393.5) + 4(-285.8)] - [-103.8 + 5(0)] = -1180.5 - 1143.2 + 103.8 = -2219.9 kJ/mol.
Ref: NCERT Class 11 Chemistry > Chapter 5: Thermodynamics > Topic: Heat Capacity and Calorimetry and Measurement of Enthalpy
Reaction: C₃H₈ + 5O₂ → 3CO₂ + 4H₂O. Moles of C₃H₈ ≈ 0.2045 mol. 1 mol needs 5 mol O₂; 0.2045 mol needs 1.0225 mol. Volume = 1.0225 × 22.4 ≈ 22.9 L.
Ref: NCERT Class 11 Chemistry > Chapter 1: Some Basic Concepts of Chemistry > Topic: Importance and Nature of Chemistry and Properties of Matter
This page is supported by advertisements. An ad blocker is stopping those ads from loading, so we cannot show the rest of the page yet. Pause the blocker for this site, then continue. We will check again automatically.
You can keep using this site after advertisements are allowed to load.
