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For KOH , [OH-] = 0.01 M = 10⁻² , pOH = -log(10⁻²) = 2 , pH = 14 - 2 = 12 .
Ref: NCERT Class 11 Chemistry > Chapter 6: Equilibrium > Topic: Acid-Base Theories - Arrhenius Bronsted-Lowry Lewis and Salts Hydrolysis
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