A 0.25 M NaOH solution is diluted by adding 300 mL of water to 200 mL of the original solution. What is the final molari
M₁V₁ = M₂V₂. 0.25 × 200 = M₂ × (200 + 300). M₂ = (0.25 × 200)/500 = 0.1 M.
Ref: NCERT Class 11 Chemistry > Chapter 1: Some Basic Concepts of Chemistry > Topic: Stoichiometry and Stoichiometric Calculations and Limiting Reagent