In SHM, which quantity is maximized when the particle’s displacement is zero?
**Oscillation of mass attached to spring** follows Hooke's law F = -k x, SHM with ω = √(k/m). Effective stiffness for two identical springs in parallel doubles, k_eff = 2k, increasing frequency by √2, while series halves stiffness to k/2, lowering frequency. Energy E = ½ k_eff A². At x = 0 (mean position), velocity is maximum ( vₘₐₓ = ω A ), and thus kinetic energy ( K = (1/2) m v² ) reaches its peak. Applying x = A cos(ωt + φ), v = -ωA sin(ωt + φ), a = -ω²x and E = ½kA² = ½mω²A², result Kinetic energy follows, reflecting SHM
Ref: NCERT > Physics Book > Oscillations > Spring-Mass System and Combination of Springs