What is the pH of a solution with [OH-] = 2.5 × 10â»Â² M?
Given: What is the pH of a solution with [OH-] = 2.5 × 10â»Â² M? These values define the system as per NCERT data. Formula: pOH = -log(2.5 × 10â»Â²) approx 1.6, pH = 14 - 1.6 = 12.4 .. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: Substituting values like 1.2 × 10â»âµ, 236 J kgâ»Â¹ Kâ»Â¹, CH₃CHâ‚‚NHâ‚‚ etc. into the formula and simplifying step by step. Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kgâ»Â¹ Kâ»Â¹, m/s², 10â»âµ are properly used as per NCERT.
Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Solutions, Topic: Concentration terms and colligative properties.