In a fuel cell, what is the cathode reaction?
Cathode: O₂ + 4H⁺ + 4e⁻ → 2H₂O .
Ref: NCERT Class 12 Chemistry > Chapter 2: Electrochemistry > Topic: Variation of Conductivity with Concentration and Measurement
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In a fuel cell operating at 298 K, the cell potential decreases from 1.23 V to 1.17 V when the [H⁺] at the cathode incre
Δ E = -(0.059/n) log ([H⁺]₂/[H⁺]₁) , 1.17 - 1.23 = -0.06 = -(0.059/n) log (1/0.1) . -0.06 = -(0.059/n) × 1 , n = (0.059/0.06) ≈ 1 , but cathode reaction O₂ + 4H⁺ + 4e⁻ , so n = 4 .
Ref: NCERT Class 12 Chemistry > Chapter 2: Electrochemistry > Topic: Nernst Equation and Gibbs Energy and Equilibrium Constant
In a fuel cell, 0.56 L of O₂ gas (STP) is consumed at the cathode. How many grams of H₂O (molar mass 18 g/mol) are produ
Cathode: O₂ + 4H⁺ + 4e⁻ → 2H₂O . Moles O₂ = (0.56/22.4) = 0.025 mol , Moles H₂O = 0.025 × 2 = 0.05 mol . Mass = 0.05 × 18 = 0.9 g .
Ref: NCERT Class 12 Chemistry > Chapter 2: Electrochemistry > Topic: Batteries - Primary Secondary and Fuel Cells
In a fuel cell, 0.56 L of O₂ gas (STP) is consumed at the cathode. How many grams of H₂O (molar mass 18 g/mol) are produ
Cathode: O₂ + 4H⁺ + 4e⁻ → 2H₂O . Moles O₂ = (0.56/22.4) = 0.025 mol , Moles H₂O = 0.025 × 2 = 0.05 mol . Mass = 0.05 × 18 = 0.9 g .
Ref: NCERT Class 12 Chemistry > Chapter 2: Electrochemistry > Topic: Batteries - Primary Secondary and Fuel Cells
In a fuel cell with H₂ and O₂, what is the cathode reaction?
Cathode: O₂(g) + 2H₂O(l) + 4e⁻ → 4OH⁻(aq) .
Ref: NCERT Class 12 Chemistry > Chapter 2: Electrochemistry > Topic: Batteries - Primary Secondary and Fuel Cells
In a fuel cell with H₂ and O₂, what is the cathode reaction?
Cathode: O₂(g) + 2H₂O(l) + 4e⁻ → 4OH⁻(aq) .
Ref: NCERT Class 12 Chemistry > Chapter 2: Electrochemistry > Topic: Batteries - Primary Secondary and Fuel Cells
In a fuel cell using H₂ and O₂, what is the anode reaction?
Anode: H₂ + 2OH⁻ → 2H₂O + 2e⁻ in basic medium.
Ref: NCERT Class 12 Chemistry > Chapter 2: Electrochemistry > Topic: Batteries - Primary Secondary and Fuel Cells
In a fuel cell using H₂ and O₂, what is the anode reaction?
Anode: H₂ + 2OH⁻ → 2H₂O + 2e⁻ in basic medium.
Ref: NCERT Class 12 Chemistry > Chapter 2: Electrochemistry > Topic: Batteries - Primary Secondary and Fuel Cells
In a fuel cell using H₂ and O₂, what is the product of the overall reaction?
Reaction: 2H₂(g) + O₂(g) → 2H₂O(l) . Product is water.
Ref: NCERT Class 12 Chemistry > Chapter 2: Electrochemistry > Topic: Batteries - Primary Secondary and Fuel Cells
In a fuel cell, what is the oxidizing agent?
Reaction: 2H₂ + O₂ → 2H₂O . O₂ is reduced, so it’s the oxidizing agent.
Ref: NCERT Class 12 Chemistry > Chapter 2: Electrochemistry > Topic: Batteries - Primary Secondary and Fuel Cells
In a fuel cell, what is the oxidizing agent?
Reaction: 2H₂ + O₂ → 2H₂O . O₂ is reduced, so it’s the oxidizing agent.
Ref: NCERT Class 12 Chemistry > Chapter 2: Electrochemistry > Topic: Batteries - Primary Secondary and Fuel Cells
A fuel cell produces 0.448 L of H₂O vapor (STP) at the cathode from O₂. How many coulombs are involved? (F = 96500 C/mol
Cathode: O₂ + 4H⁺ + 4e⁻ → 2H₂O . 2 mol H₂O (44.8 L) requires 4F. Moles = (0.448/22.4) = 0.02 mol , Charge = (0.02/2) × 4 × 96500 = 0.04 × 96500 = 3860 C .
Ref: NCERT Class 12 Chemistry > Chapter 2: Electrochemistry > Topic: Batteries - Primary Secondary and Fuel Cells