How many grams of CuSO₄ are required to produce 12.8 g of Cu with excess Zn? (Molar masses: CuSO₄ = 159.5 g/mol, Cu = 64
Reaction: CuSO₄ + Zn → Cu + ZnSO₄. Moles of Cu = 12.8/64 = 0.2 mol. 1 mol Cu from 1 mol CuSO₄; mass = 0.2 × 159.5 = 31.9 g.
Ref: NCERT Class 11 Chemistry > Chapter 1: Some Basic Concepts of Chemistry > Topic: Importance and Nature of Chemistry and Properties of Matter