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Pi = MRT . Pi = 0.02 × 0.0821 × 300 ≈ 0.492 atm .
Ref: NCERT Class 12 Chemistry > Chapter 1: Solutions > Topic: Colligative Properties - Osmotic Pressure and Reverse Osmosis
Moles of solute = (9/90) = 0.1 mol . Volume = 450 mL = 0.45 L. Molarity = (0.1/0.45) ≈ 0.2222 M .
Ref: NCERT Class 12 Chemistry > Chapter 1: Solutions > Topic: Colligative Properties - Osmotic Pressure and Reverse Osmosis
Pi = i · M · RT . 1.845 = i × 0.25 × 0.0821 × 300 . i = (1.845/0.25 × 24.63) ≈ 0.3 × 6 = 1.8 . i = 1 + α , 1.8 = 1 + α , α = 0.8 .
Ref: NCERT Class 12 Chemistry > Chapter 1: Solutions > Topic: Colligative Properties - Osmotic Pressure and Reverse Osmosis
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