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2-Methylpropan-2-ol ((CH₃)3COH) dehydrates with conc. H₂SO₄ to form 2-methylpropene (CH₂=C(CH₃)CH₃), following Saytzeff’s rule.
Ref: NCERT Class 12 Chemistry > Chapter 7: Alcohols, Phenols and Ethers > Topic: Chemical Reactions of Phenols and Ethers and Uses
Conc. H₂SO₄ at 140°C rapidly dehydrates 2-methylpropan-2-ol, a tertiary alcohol, to 2-methylpropene via a stable tertiary carbocation in an E₁ mechanism.
Ref: NCERT Class 12 Chemistry > Chapter 7: Alcohols, Phenols and Ethers > Topic: Chemical Reactions of Alcohols - Dehydration Oxidation Esterification
Primary alcohols undergo dehydration to give mainly terminal alkenes like but-1-ene.
Ref: NCERT Class 12 Chemistry > Chapter 7: Alcohols, Phenols and Ethers > Topic: Chemical Reactions of Alcohols - Dehydration Oxidation Esterification
Elimination (E₂) of (CH₃)2CHCH₂CH₂Br with alcoholic KOH forms (CH₃)2C=CHCH₃ (2-methyl-2-butene) per Zaitsev's rule.
Ref: NCERT Class 12 Chemistry > Chapter 6: Haloalkanes and Haloarenes > Topic: Elimination Reactions and Reaction with Metals and Other Reactions
Elimination (E₂) of CH₃CH₂CH₂CH₂CH₂Br (1-bromopentane) with alcoholic KOH forms 1-pentene ( CH₃CH₂CH₂CH=CH₂ ).
Ref: NCERT Class 12 Chemistry > Chapter 6: Haloalkanes and Haloarenes > Topic: Elimination Reactions and Reaction with Metals and Other Reactions
Primary halides undergo elimination (E₂) slowest due to less stable transition states. CH₃CH₂CH₂Cl reacts slowest among the options.
Ref: NCERT Class 12 Chemistry > Chapter 6: Haloalkanes and Haloarenes > Topic: Elimination Reactions and Reaction with Metals and Other Reactions
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