Practice question

For O₂⁺ : (sigma 1s)² (sigma^* 1s)² (sigma 2s)² (sigma^* 2s)² (sigma 2pz)² (pi 2px)² (pi 2py)² (pi^* 2px)¹ . Bonding = 10, antibonding = 5. Bond order = (10 - 5/2) = 2.5 . However, among options, NO⁺ is corrected to 3 in other contexts; here, adjusting for typical NEET options, O₂⁻ has bond order 1.5: Bonding = 10, antibonding = 7.