Practice question

MCQ

Question

Which complex can exist as a pair of enantiomers?

Options

Choose one · Correct answer highlighted

[Co(NH₃)6]3+ [Co(en)3]3+ Correct [Ni(NH₃)4]2+ [Fe(CN)6]4−

Explanation

[Co(en)3]3+ (octahedral) with 3 bidentate en ligands lacks symmetry, forming non-superimposable mirror images (enantiomers).

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