Skip to content

Question

The ratio of the radii of the third orbit of He⁺ to the second orbit of Li²⁺ is: (r₁ for H = 5.29 × 10⁻¹¹ m)

Options

Choose one · Correct answer highlighted

Explanation

r₃(He⁺)/r₂(Li²⁺) ≈ 3.375.

Discussion

Comments

0 comments

No comments yet. Be the first to start the discussion.