Skip to content
Login Register

Practice question

MCQ

Question

For H₂(g) + I₂(g) <=> 2HI(g) , Kc = 50 at 700 K. If 0.2 mol H₂ and 0.3 mol I₂ are in a 1 L vessel, what is [HI] at equilibrium?

Options

Choose one · Correct answer highlighted

Explanation

Initial: [H₂] = 0.2 M , [I₂] = 0.3 M , [HI] = 0 . Let 2x = [HI] , [H₂] = 0.2 - x , [I₂] = 0.3 - x . Kc = ([HI]²/[H₂][I₂]) = ((2x)²/(0.2 - x)(0.3 - x)) = 50 , 4x² = 50 (0.06 - 0.5x + x²) , 46x² - 25x + 3 = 0 , x ≈ 0.15 , [HI] = 0.3 M .

Discussion

Comments

0 comments

No comments yet. Be the first to start the discussion.

Related blogs

Guides and insights connected to this topic