Practice question
Question
For H₂(g) + Br₂(g) → 2HBr(g), Δ H = -72.6 kJ/mol, Δ S = 114 J/K at 298 K. What is Δ G?
Explanation
Δ G = Δ H - TΔ S = -72.6 - 298 × 0.114 = -72.6 - 33.97 = -106.57 kJ/mol.
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