Practice question
Question
Calculate the heat absorbed when 40 g of iron is heated from 20°C to 100°C at constant pressure. (Cp = 25.1 J/mol·K, molar mass = 56 g/mol)
Explanation
Moles = 40 / 56 = 0.7143 mol, Δ T = 100 - 20 = 80 K, qp = nCpΔ T = 0.7143 × 25.1 × 80 = 1434.3 J = 1.434 kJ.