Practice question
Question
A solution contains 5 ppm of NaCl by mass in water. What is its molality? (Molar mass: NaCl = 58.5 g/mol)
Explanation
5 ppm = 5 g NaCl in 10⁶ g water. Moles = 5 / 58.5 ≈ 0.0855 mol. Mass of solvent = 10⁶ g = 1000 kg. Molality = 0.0855 / 1000 ≈ 8.55 × 10⁻⁵ m.
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