Practice question

Given: A photon has an energy of 4.14 × 10⁻¹⁹ J . What is its frequency? (Take h = 6.63 × 10⁻³⁴ J s ) These values define the system as per NCERT data. Formula: Energy of photon E = h v. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: v = E/h = frac4.14 × 10⁻¹⁹⁶.63 × 10⁻³⁴ approx 6.24 × 10¹⁴ Hz . Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.