Practice question

Given: A particle of mass 2.0 × 10⁻²⁹ kg has a de Broglie wavelength of 1.0 nm . What is its momentum? These values define the system as per NCERT data. Formula: lambda = h/p Rightarrow p = h/lambda = frac6.63 × 10⁻³⁴¹.0 × 10⁻⁹= 6.63 × 10⁻²⁵ kg m/s .. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: Substituting values like 1.2 × 10⁻⁵, 236 J kg⁻¹ K⁻¹, CH₃CH₂NH₂ etc. into the formula and simplifying step by step. Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.