Practice question
Question
A particle in SHM has \( a = -9 x \) (in SI units). What is its period?
Explanation
**Angular frequency** ω = 2πf = 2π/T characterizes rapidity, independent of amplitude for SHM. Phase constant φ shifts sine/cosine, allowing any initial condition, e.g., x(0)=0 requires φ=0 for sine form. Displacement, velocity, acceleration share ω but differ in phase by 90° and 180°. For SHM, a = -ω² x . Given a = -9 x , ω² = 9 ⇒ ω = 3 rad/s . T = (2π/ω) = (2π/3) ≈ 2.09 s . Applying x = A cos(ωt + φ), v = -ωA sin(ωt + φ), a = -ω²x and E = ½kA² = ½mω²A², result 2.09 s follows, reflecting SHM dependence on amplitude A, ω and system parameters.
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