Practice question
Question
A gas has a C_v of 20.8 J mol^{-1 K^{-1. What is the ratio of specific heats (γ)? (R = 8.31 J mol^{-1 K^{-1)
Explanation
Given:
A gas has a C_v of 20.8 J mol^{-1 K^{-1. What is the ratio of specific heats (γ)? (R = 8.31 J mol^{-1 K^{-1)
Formula:
C_p = C_v + R = 20.8 + 8.31 = 29.11 J mol^{-1 K^{-1.
Substitution & Calculation:
γ = C_p/C_v = 29.11/20.8 approx 1.40.
Final Result:
The computed value matches expected outcome and confirms correct choice as per latest NCERT 2026-27.
Discussion
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