Practice question
Question
A body loses \( 3.2 \times 10^{-8} \, \text{C} \) of charge when rubbed. How many electrons were
transferred from it?
Explanation
**Fundamental property of charge** includes additivity and quantization, meaning net charge equals algebraic sum of constituents and each is multiple of e. When rod loses charge, electron removal is inferred, and n = q/e gives transferred count. Losing charge means electrons are removed, so charge is positive. q = n e , e = 1.6 × 10⁻¹⁹ C . n = (q/|e|) = (3.2 × 10⁻⁸/1.6 × 10⁻¹⁹) = 2 × 10¹¹ . Substituting values gives 2 × 10¹¹, which matches expected magnitude for this electrostatic configuration, confirming Coulomb's and Gauss's principles and charge quantization consistency.
Discussion
Comments
Please log in to join the discussion.
Login to commentNo comments yet. Be the first to start the discussion.