Practice question
Question
How much heat is required to convert 1 g of water from liquid at 100^circ C to vapor at 100^circ C at 1 atm ? (Latent heat = 2256 J/g )
Explanation
**Latent heat** energy needed for phase change without temperature change, overcomes intermolecular forces, e.g., heating ice at 0°C to water at 0°C requires 334 kJ/kg, then heating water to 100°C requires c ΔT, then vaporization 2260 kJ/kg, illustrating two types of heat. Heat: Δ Q = m L . m = 1 g , L = 2256 J/g . Δ Q = 1 × 2256 = 2256 J . Using first law ΔU = Q - W, W = ∫ P dV, isobaric W = P ΔV, isothermal W = n R T ln(V₂/V₁), adiabatic P V^γ = const and η = 1 - T_c/T_h,
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