Practice question

**Isobaric and isothermal** are fundamental thermodynamic processes, isobaric P constant horizontal line on P-V diagram, isothermal hyperbolic P = n R T/V, work equals area under curve, isothermal work larger than adiabatic for same volume change because pressure higher. First Law: Δ Q = Δ U + Δ W . Δ Q = 700 , Δ W = -300 (work done on system, negative work by system). 700 = Δ U - 300 ⇒ Δ U = 700 + 300 = 1000 J . Using first law ΔU = Q - W, W = ∫ P dV, isobaric W = P ΔV, isothermal W =