Practice question
Question
Two identical springs (\( k = 60 \, \text{N/m} \)) are attached to a \( 1.2 \, \text{kg} \) mass as in
Fig. 13.14. What is the frequency?
Explanation
**Mass-spring dynamics** show T depends on mass and stiffness, independent of amplitude for ideal spring. Given T and m, k = 4π² m/T² extracted, and energy E = ½ k A² connects amplitude to total mechanical energy, illustrating isochronism. Effective kₑff = 2k = 2 × 60 = 120 N/m . ω = √((kₑff/m)) = √((120/1.2)) = √(100) = 10 rad/s . v = (ω/2π) = (10/2 × 3.14) ≈ 1.59 Hz . Applying x = A cos(ωt + φ), v = -ωA sin(ωt + φ), a = -ω²x and E = ½kA² = ½mω²A², result 1.59 Hz follows, reflecting SHM dependence on amplitude A, ω and system parameters.
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