Practice question
Question
The uncertainty in the position of an electron is 1.0 × 10⁻¹⁰ m. What is the minimum uncertainty in its velocity? (h = 6.626 × 10⁻³⁴ J s, mₑ = 9.1 × 10⁻³¹ kg)
Explanation
Δv ≥ h/(4π m Δx) ≈ 5.8×10⁵ m s⁻¹.
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