Practice question
Question
In a lead storage battery during discharge, 0.1515 g of PbSO₄ (molar mass 303 g/mol) is formed at the anode. How many coulombs are involved? (F = 96500 C/mol)
Explanation
Anode: Pb + SO₄²⁻ → PbSO₄ + 2e⁻ . Moles = (0.1515/303) = 0.0005 mol , Charge = 0.0005 × 2 × 96500 = 96.5 C .
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