Practice question
Question
In 2K₂Cr₂O₇ + 2H₂O + 3S → 4KOH + 2Cr₂O₃ + 3SO₂, which element undergoes the largest decrease in oxidation number?
Explanation
Cr (+6 in Cr₂O₇²−) to +3 in Cr₂O₃: -3. S (0) to +4 in SO₂: +4. Cr decreases most.
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