Practice question
Question
How much heat is required to raise the temperature of 0.5 kg of aluminium from 25^circ C to 55^circ C ? (Specific heat of aluminium = 900 J kg⁻¹ K⁻¹ )
Explanation
**Zeroth law of thermodynamics** if two systems A and B each in thermal equilibrium with third C, then A and B in equilibrium with each other, defines temperature as property that is same for systems in thermal equilibrium, basis for thermometer, temperature scale, thermal equilibrium means no net heat flow, same temperature. Δ Q = m s Δ T . m = 0.5 , s = 900 , Δ T = 55 - 25 = 30 . Δ Q = 0.5 × 900 × 30 = 13500 J . Using first law ΔU = Q - W, W = ∫ P dV, isobaric W =
Discussion
Comments
Please log in to join the discussion.
Login to commentNo comments yet. Be the first to start the discussion.