Practice question
Question
How many grams of KCl (molar mass = 74.5 g/mol) are needed to prepare 250 mL of a 0.4 M solution?
Explanation
Moles of KCl = 0.4 × 0.25 = 0.1 mol . Mass = 0.1 × 74.5 = 7.45 g .
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