Practice question

MCQ

Question

How many grams of CaCl₂ (molar mass = 111 g/mol) are needed to prepare 600 mL of a 0.2 M solution?

Options

Choose one · Correct answer highlighted

13 g 13.32 g Correct 14 g 12.5 g

Explanation

Moles of CaCl₂ = 0.2 × 0.6 = 0.12 mol . Mass = 0.12 × 111 = 13.32 g .

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