For PbSO₄(s) Pb²⁺(aq) + SO₄²⁻(aq) , Ksp = 1.6 × 10⁻⁸ . In a 0.02 M Na₂SO₄ solution, what is [Pb²⁺] at equilibrium?

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For PbSO₄(s) <=> Pb²⁺(aq) + SO₄²⁻(aq) , Ksp = 1.6 × 10⁻⁸ . In a 0.02 M Na₂SO₄ solution, what is [Pb²⁺] at equilibrium?

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1.6 × 10⁻⁸ 8.0 × 10⁻⁷ Correct 4.0 × 10⁻⁷ 2.0 × 10⁻⁶

Ksp = [Pb²⁺][SO₄²⁻] = 1.6 × 10⁻⁸ , [SO₄²⁻] ≈ 0.02 , [Pb²⁺] = (1.6 × 10⁻⁸/0.02) = 8.0 × 10⁻⁷ M .

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