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Question

An electron in the third orbit of a hydrogen atom has a velocity of 7.3 × 10⁵ m s⁻¹. What is its de Broglie wavelength? (h = 6.626 × 10⁻³⁴ J s, mₑ = 9.1 × 10⁻³¹ kg)

Options

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Explanation

λ = h/(mv) ≈ 9.98×10⁻¹⁰ m.

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