Practice question
Question
A solution of a non-volatile solute in water boils at 100.52°C at 1 atm. What is the molality of the solution? ( Kb = 0.52 K kg mol⁻¹ )
Explanation
Δ Tb = Kb · m . 100.52 - 100 = 0.52 · m . m = (0.52/0.52) = 1 mol/kg .
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