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Practice question

MCQ

Question

A solution is made by dissolving 20 g of a solute (molar mass = 40 g/mol) in water. If the freezing point depression is 0.465°C and Kf = 1.86 K kg mol⁻¹ , what is the total mass of the solution?

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Explanation

Moles = (20/40) = 0.5 . Δ Tf = Kf · m . 0.465 = 1.86 × (0.5/w) , w = (0.5 × 1.86/0.465) ≈ 2 kg = 2000 g . Total mass = 20 + 2000 = 2020 g .

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