Practice question
Question
A reaction’s rate increases by 9 times when the temperature rises from 330 K to 350 K. What is the activation energy (R = 8.314 J mol⁻¹ K⁻¹)?
Explanation
log 9 = Ea/(2.303R) × (20)/(330×350) → Ea ≈ 105.5 kJ mol⁻¹.
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