Practice question

MCQ

Question

A reaction’s rate increases by 2.83 times when the temperature rises from 320 K to 330 K. What is the activation energy (R = 8.314 J mol⁻¹ K⁻¹)?

Options

Choose one · Correct answer highlighted

45.7 kJ mol⁻¹ 68.6 kJ mol⁻¹ 114.2 kJ mol⁻¹ 91.4 kJ mol⁻¹ Correct

Explanation

log(k₂/k₁) = Ea/(2.303R) × (T₂-T₁)/(T₁T₂). log 2.83 ≈ 0.452 → Ea ≈ 91.4 kJ mol⁻¹.

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