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Question

A pendulum has \( L = 0.25 \, \text{m}, g = 10 \, \text{m/s}^2 \). What is its angular frequency?

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Explanation

**General equation of SHM** x = A sin(ωt + φ) or A cos(ωt + φ) includes amplitude A (m), angular frequency ω = √(k/m) (rad/s) for spring system, and initial phase φ (rad) setting t=0 position. Phase (ωt + φ) determines instantaneous state, phase difference Δφ governs interference of two SHM motions. ω = √((g/L)) = √((10/0.25)) = √(40) ≈ 6.32 rad/s . Applying x = A cos(ωt + φ), v = -ωA sin(ωt + φ), a = -ω²x and E = ½kA² = ½mω²A², result 6.32 rad/s follows, reflecting SHM dependence on amplitude A, ω and system parameters.

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