Practice question
Question
A particle in SHM has an amplitude of \( 8 \, \text{cm} \) and a frequency of \( 2 \, \text{Hz} \).
What is its maximum acceleration? (Take \( \pi = 3.14 \))
Explanation
**SHM representation** using sine or cosine equivalent with phase offset, ω relates to system parameters like mass and stiffness. Understanding ω and φ permits prediction of position at any time and comparison of two SHM via phase difference Δφ = φ₂ - φ₁. Maximum acceleration: aₘₐₓ = ω² A . ω = 2π v = 2 × 3.14 × 2 = 12.56 rad/s . A = 8 cm = 0.08 m . aₘₐₓ = (12.56)² × 0.08 ≈ 157.75 × 0.08 ≈ 12.62 m/s² . Applying x = A cos(ωt + φ), v = -ωA sin(ωt + φ), a = -ω²x and E = ½kA²
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