Practice question
Question
A particle in SHM has \( a = -64 x \) (in SI units). What is its period?
Explanation
**Resonance phenomenon** amplifies response when driving frequency matches natural frequency ω_d ≈ ω₀, large amplitude even with small F₀, as damping limits growth. Natural frequency determined by system parameters, resonance condition crucial for understanding vibrations and energy absorption, e.g., bridge collapse, tuning. For SHM, a = -ω² x . Given a = -64 x , ω² = 64 ⇒ ω = 8 rad/s . Period: T = (2π/ω) = (2π/8) = (π/4) ≈ 0.785 s . Applying x = A cos(ωt + φ), v = -ωA sin(ωt + φ), a = -ω²x and E = ½kA² = ½mω²A², result 0.785 s follows, reflecting SHM dependence
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